想必现在有很多小伙伴对于判断并改正$\dfrac{{\displaystyle \dfrac{{\displaystyle 6\underset{\begin{array}{lll}6& & \end{array}}{\overset{\begin{array}{lll}& 1& 6\end{array}}{\require{enclose}\enclose{longdiv}{ \begin{array}{lll}6& 3& 6\end{array}}}}}}{\begin{array}{llll}& & 3& 6\\ & & 3& 6\end{array}}}}{\begin{array}{llll}& & & 0\end{array}}$（）改正：","title_text":"判断并改正$\dfrac{{\displaystyle \dfrac{{\displaystyle 6\underset{\begin{array}{lll}6 \end{array}}{\overset{\begin{array}{lll} 1 6\end{array}}{\require{enclose}\enclose{longdiv}{ \begin{array}{lll}6 3 6\end{array}}}}}}{\begin{array}{llll} 3 6\\ 3 6\end{array}}}}{\begin{array}{llll} 0\end{array}}$（）改正：方面的知识都比较想要了解，那么今天小好小编就为大家收集了一些关于判断并改正$\dfrac{{\displaystyle \dfrac{{\displaystyle 6\underset{\begin{array}{lll}6& & \end{array}}{\overset{\begin{array}{lll}& 1& 6\end{array}}{\require{enclose}\enclose{longdiv}{ \begin{array}{lll}6& 3& 6\end{array}}}}}}{\begin{array}{llll}& & 3& 6\\ & & 3& 6\end{array}}}}{\begin{array}{llll}& & & 0\end{array}}$（）改正：","title_text":"判断并改正$\dfrac{{\displaystyle \dfrac{{\displaystyle 6\underset{\begin{array}{lll}6 \end{array}}{\overset{\begin{array}{lll} 1 6\end{array}}{\require{enclose}\enclose{longdiv}{ \begin{array}{lll}6 3 6\end{array}}}}}}{\begin{array}{llll} 3 6\\ 3 6\end{array}}}}{\begin{array}{llll} 0\end{array}}$（）改正：方面的知识分享给大家，希望大家会喜欢哦。

【答案】

✕

改正：

【解析】

改正：

故答案为：✕

本文到此结束，希望对大家有所帮助。

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